大一/物理/作业

$$v=\frac{\sqrt 3}2c\\ \Delta t=-\frac{\sqrt 3}3\times10^{-5}\text s$$ $$p_1=\sqrt{2m_eUe}\\ p_2=\frac{\sqrt{2m_eeUc^2+e^2U^2}}c$$ $$E=\frac{\varepsilon _0m_0c^2}{m_0c^2+\varepsilon _0(1-\cos\theta)}$$ $$\overline{E_k}=\frac14kA^2,\overline{E_p}=\frac14kA^2$$ $$a:0,b:\frac{\pi}3,c:\pi\\ d:\frac{2\pi}3,e:-\frac{2\pi}3\\ x=5\cos\left(\frac{\pi}{1.2}t-\frac{\pi}3\right)$$ $$A=\sqrt{\frac8{125}},E_p=0.2\text{J}$$ $$\frac{2\pi}k,I=\frac12\rho A^2 \frac{\omega^3}k$$ $$I=0.09\text{W}\cdot\text{m}^{-2}\\ \overline{w}= 2.647\times10^{-4}\text{J}\cdot\text{s}\cdot\text{m}^{-3}$$ $$y=0.1\cos\left[165\pi\left(t-\frac x{330}\right)+\pi\right]\text{m}$$ $$\frac{1.5\times20}{293}+\frac{1\times V}{293}=\frac{7.5\times20}{298}\\ \Rightarrow V=117.483 \text{L}$$ $$W =\frac{C}2(\frac1{V_1^2}-\frac1{V_2^2})\\$$ $$Q_1=n(\frac i2+1)R\Delta T=500\text{J}\\ Q_2=700\text{J}$$ $$W=\frac{3200}{293}\text{KW}=10.92\text{KW}$$ $$1. N\int_{v_0}^{\infty}f(v)\text{d}v\\ 2. \frac{\displaystyle\int_{v_0}^{\infty}vf(v)\text{d}v}{\displaystyle\int_{v_0}^{\infty}f(v)\text{d}v}\\ 3. \int_{v_0}^{\infty}f(v)\text{d}v$$